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How do i convince someone that $1+1=2$ may not necessarily be true We are basically asking that what transformation is required to get back to the identity transformation whose basis vectors are i ^ (1,0) and j ^ (0,1). I once read that some mathematicians provided a very length proof of $1+1=2$
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Can you think of some way to 这个极限的推广形式 lim (x→0) (1+kx)^ (1/x) = e^k 也经常被使用。 这个极限的发现和研究在数学发展史上具有重要意义，它连接了离散与连续、代数与分析等多个数学领域，是理解指数增长和自然对数的基础。 11 there are multiple ways of writing out a given complex number, or a number in general
The complex numbers are a field
It's a fundamental formula not only in arithmetic but also in the whole of math Is there a proof for it or is it just assumed? 注1：【】代表软件中的功能文字 注2：同一台电脑，只需要设置一次，以后都可以直接使用 注3：如果觉得原先设置的格式不是自己想要的，可以继续点击【多级列表】——【定义新多级列表】，找到相应的位置进行修改 There are infinitely many possible values for $1^i$, corresponding to different branches of the complex logarithm
The confusing point here is that the formula $1^x = 1$ is not part of the definition of complex exponentiation, although it is an immediate consequence of the definition of natural number exponentiation. 两边求和，我们有 ln (n+1)<1/1+1/2+1/3+1/4+……+1/n 容易的， \lim _ {n\rightarrow +\infty }\ln \left ( n+1\right) =+\infty ，所以这个和是无界的，不收敛。 Intending on marking as accepted, because i'm no mathematician and this response makes sense to a commoner However, i'm still curious why there is 1 way to permute 0 things, instead of 0 ways.
1/8 1/4 3/8 1/2 5/8 3/4 7/8 英寸。 this is an arithmetic sequence since there is a common difference between each term
In this case, adding 18 to the previous term in the sequence gives the next term In other words, an=a1+d (n−1)
